We know that for every 5 red bricks there were 2 gray bricks.
The total amount of red bricks and grey bricks in this sample is 7.
5 red bricks + 2 grey bricks = 7 bricks
Now, we divide 175 "total number of bricks used" by 7 "5 red bricks + 2 grey bricks = 7 bricks" and we will get a quotient of 25.
Now we know that 25 bricks is 
of the wall. The gray bricks are 
so we can multiply 25 by 2 and we will get a product of 50. If 1/7 = 25 grey bricks so 2/7 would be the grey bricks.
175 - 50 = number of red bricks.
Therefore, there were 125 red bricks.
Answer:
8500
Step-by-step explanation:
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The percent of runners between these two times is 47.72.
We find the z-scores associated with each end of this interval using the formula
z=(X-μ)/σ
For the lower end,
z=(4.11-4.41)/0.15 = -0.3/0.15 = -2
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.0228.
For the upper end:
z=(4.41-4.41)/0.15 = 0/0.15 = 0
Using a z-table we see that the area to the left of, less than, this score is 0.5000.
We want the area between these times, so we subtract:
0.5000-0.0228 = 0.4772
This corresponds with 47.72%.
Answer:
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