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Vlad1618 [11]
3 years ago
15

I need help for tha pre-test?​

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

1.) B

2.) C

3.) D

4.) B

5.) A

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Let h(x) = (g o f)(x) = sqrt{x+3}
Debora [2.8K]
I am assuming you meant to write the following options

A. f(x)=x+3; g(x)=√x
B. f(x)=x; g(x)=x+3
C. f(x)=√x; g(x)=x+3
D. f(x)=3x; g(x)=√x

You need to find a fucntion f(x) that once evaluated in g(x) gives us as a result h(x)

h(x) =  g(f(x))

Looking at the options, the answer is A.

g(f(x)) = sqrt(f(x)) = sqrt (x + 3) = h(x)
8 0
3 years ago
Read 2 more answers
AND<br> - 4x + 3 &lt; -6<br> 12.c<br> · 39 &lt; 9
Scilla [17]

Answer:

the answer is 30 u were close u idiot but you aren't good enough dorry but u Americans are stupid and hell

scam

3 0
3 years ago
Calcular x en: los datos q faltan
Taya2010 [7]
Answer:

x = 13

Step-by-step explanation:

No se exactamente como decir esto porque yo ayudo la majoria de los usuario en ingles pero hay que usar un método para describir a x

Un método que se llama Pythagorean theorem

Pythagorean theorem: a^2 + b^2 = c^2 donde a^2 = 5 b^2 = 12 y c^2 = x

Entonces…

5^2 + 12^2 = c^2

Nota: podemos ver que esto esta bien porque el sum de los dos lados suma el mas largo.

Ahora

25 + 144 = c^2

c^2 = 169

Pero eso no puede ser la respuesta porque no tiene sentido a que x sea un lado que mide 169 entonces tenemos que usar sqrt rt

sqrt rt de 169 = 13

x = 13
4 0
3 years ago
Can anyone help me. Will give you all my points and brainliest:)
PilotLPTM [1.2K]

See the attachments for the answer :)

8 0
3 years ago
How do I find Trig ratios
nadya68 [22]

Trig ratios can only be used on right triangles with acute measures.

If given an angle and there are adjacent and opposite sides, then use tan(opposite/adjacent)

If given an angle and there is an adjacent side and a hypotenuse, then use cosine(adjacent/hypotenuse)

If given an angle and there is an opposite and adjacent side, then use sin(opposite/hypotenuse)

A common mnemonic device used to memorize the trig rules is SOH-CAH-TOA

8 0
3 years ago
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