What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? Drag and drop the co
rrect answer into the box. 373.25311.04259.243.2 ft²
       
      
                
     
    
    
    
    
    2 answers:
            
              
              
                
                
S.A=s^2×6
S.A=7.2^2×6
S.A=311.04 ft^2 is your final answer. Hope it help!
                                
             
                    
              
              
                
                
A cube has 6 equal sides all having an area equal to a side length squared, or mathematically:
A=6s^2, where s is the length of a side...we are given that s=7.2 so
A=6(7.2^2)
A=311.04 ft^2
                                
             
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