All categories

3 years ago

What is the area of trapezoid DEFG with coordinates D(2,3) E(4,3) F(6,1) G(2,1)?

2 answers:

8 0

The answer you are looking for is 6 square units I hope I am right sorry if I am wrong because I need to see the picture

Salsk061 [2.6K]3 years ago

4 0

Answer:

Answer is 6

Step-by-step explanation:

I took the quiz

You might be interested in

Choose the best answer. The diagonals of a rectangle:

erastovalidia [21]

C.) Are the same length

How you know-

No matter how long the rectangle is the diagonals always will measure the same length. Think about two sides of a square, they have to equal the same length because if they were not the same then the shape wouldn't be a square.

3 0

3 years ago

Read 2 more answers

If f(5)= 3, write an ordered pair that must be on the graph of y = f(x + 1) + 2

vlabodo [156]

f(5) = 3 means (5,3) is on the graph of f.

On the new graph, y = f(x+1) + 2, what do the +1 and +2 do?

Things inside the function notation inpact the x-values, since that's where x sits.

This outside the f(x) notation impact the y-values, since those are done after you've evaluated the function.

"+1" on the inside shifts every point to the left 1 unit. (Inside changes are almost always opposite from what it looks like it would do.)

"+2" on the outside will shift every point up by 2 units.

So what do you get if you take (5,3) and shift it left 1 and up 2?

8 0

3 years ago

1.4(0.5x+4.2y)−3.5(0.2x−1.5y) simplify lots of points

Vilka [71]

1,4(0,5x + 4,2y) - 3,5(0,2x - 1,5y)

1,4.0,5x + 1,4.4,2y - 3,5.0,2x + 3,5.1,5y

0,7x + 5,88y - 0,7x + 5,25y

0,7x - 0,7x + 5,88y + 5,25y

11,13y

7 0

3 years ago

A shipping box is the shape a cube. Each side measures 3c^6d^2 inches. Express the volume of the cube as a monomial?

Maurinko [17]

I hope this helps you

3 0

3 years ago

Read 2 more answers

3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared

navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

$\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end$

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

8 0

2 years ago