All categories

2 years ago

What is the area of trapezoid DEFG with coordinates D(2,3) E(4,3) F(6,1) G(2,1)?

2 answers:

8 0

The answer you are looking for is 6 square units I hope I am right sorry if I am wrong because I need to see the picture

Salsk061 [2.6K]2 years ago

4 0

Answer:

Answer is 6

Step-by-step explanation:

I took the quiz

You might be interested in

What is the y-intercept of a line with the equation (y - 3) = 5(x + 2)?

Nookie1986 [14]

The y-intercept would be (0, 13)

7 0

2 years ago

The fractions of -42/-45 and 14/15 are equivalent

FromTheMoon [43]

Yes, that is true, you have to simplify -42/-45 to be able to see if they are equivalant.
$\frac{ - 42}{ - 45} = \frac{14}{15}$

8 0

3 years ago

-8(8 - x) = 4/5(x + 10)

Vedmedyk [2.9K]

Answer:

x = 10

Step-by-step explanation:

Solve for x:

-8 (8 - x) = (4 (x + 10))/5

Multiply both sides by 5:

-8×5 (8 - x) = (5×4 (x + 10))/5

(5×4 (x + 10))/5 = 5/5×4 (x + 10) = 4 (x + 10):

-8×5 (8 - x) = 4 (x + 10)

5 (-8) = -40:

-40 (8 - x) = 4 (x + 10)

Expand out terms of the left hand side:

40 x - 320 = 4 (x + 10)

Expand out terms of the right hand side:

40 x - 320 = 4 x + 40

Subtract 4 x from both sides:

(40 x - 4 x) - 320 = (4 x - 4 x) + 40

40 x - 4 x = 36 x:

36 x - 320 = (4 x - 4 x) + 40

4 x - 4 x = 0:

36 x - 320 = 40

Add 320 to both sides:

36 x + (320 - 320) = 320 + 40

320 - 320 = 0:

36 x = 40 + 320

40 + 320 = 360:

36 x = 360

Divide both sides of 36 x = 360 by 36:

(36 x)/36 = 360/36

36/36 = 1:

x = 360/36

The gcd of 360 and 36 is 36, so 360/36 = (36×10)/(36×1) = 36/36×10 = 10:

Answer: x = 10

7 0

3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)