What is (2x + 1)(3x + 7) simplified
2 answers:
Answer:
+17x+7 and zeros are -7/3 and -1/2
Step-by-step explanation:
You multiply every property by every variable not in their own parentheses.
2x*3x=6x^2
2x*7=14x
3x*1=3x
7*1=7
6x^2+3x+14x+7
add like variables together 3x+14x
6x^2+17x+7
( To get the zeros just make each equation in the parentheses equal to zero and solve for x.) ex 2x+1=0 x=-1/2
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Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴
∵ DE : CD = 5 : 3
∴
∴ KD = 5/3 KC
∵ KE = KC + 8
∵
∴
∴
∴
∴
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17