4.5 ... 9/2 and you will get the answer
The type and number of solutions is (b) two imaginary solutions.
<h3>How to determine the type and number of solutions?</h3>
The equation is given as:
3x² + 5x + 5 = 0
A quadratic equation can be represented as:
ax^2 + bx + c = 0
Where, the discriminant (d) is
d = b^2 - 4ac
So, we have
d = 5^2 - 4 * 3 * 5
Evaluate
d = -35
The value of d is negative
This means that the equation has only imaginary solutions
Hence, the type and number of solutions is (b) two imaginary solutions.
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The first odd number before 231 which would be on the same side of the hall is 229. The first odd number after would be 233.
On the odd side of the hall, the order would be room 229, room 231, room 233.
Answer:
6x + 10
Step-by-step explanation:
2+4=6
and 10 doesn't have an x next to it so it doesn't count
Y = 4x - 9 and y = x-3 so the two right sides (4x-9 and x-3) must be equal
4x-9 = x-3
Let's solve for x
4x-9 = x-3
4x-9+9 = x-3+9 ... add 9 to both sides
4x = x+6
4x-x = x+6-x ... subtract x from both sides
3x = 6
3x/3 = 6/3 ... divide both sides by 3
x = 2
If x = 2, then y is...
y = 4*x - 9 = 4*2-9 = 8-9 = -1
which can also be found by
y = x-3 = 2-3 = -1
So overall x = 2 and y = -1
We have the ordered pair (x,y) = (2,-1)