any of the 34 cars can finish first
any of the remaining 33 cars can finish second
any of the remaining 32 cars can finish third
Thus, the top 3 finishes can be done in (34)(33)(32) = 35904 ways
Answer:
B
Step-by-step explanation:
anything.
I need at least 20 characters, so: blablabla.
;)
Answer:
f inverse x = -x+4/5
Step-by-step explanation: