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PolarNik [594]
3 years ago
8

Y varies inversely with x and y = 5 when x = 2.   Which is the inverse variation equation for the relationship?  

Mathematics
1 answer:
klio [65]3 years ago
6 0
Y =k/x is the inverse function.
5 = k/2 ; 10 = k ;

y = 10/x
Letter C
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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

x=(7)+(-4)t

x=7-4t

Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

5 0
3 years ago
NEED ASAP please!!!!!
stepan [7]

I think it's 1/4 that's my answer

7 0
3 years ago
Read 2 more answers
Idk how to solve these questions
Anuta_ua [19.1K]
Of means multiply

3/5 *n=30

3/5 5/3 cancels than you do 30 *5/3 =50

The answer is 50 you can check your answer by doing 3/5 *50=150/5 or 30 so it's correct .
5 0
3 years ago
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Helppppppppppppp ASAP
Ivan

The formula for N choose K is given as:

C(n, k)= \frac{n!}{[k!(n-k)!]  }

Where,

n is the total numbers.

k is the number of the selected item.

Options C is correct.

6 0
3 years ago
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A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol
Phoenix [80]

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

4 0
3 years ago
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