We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
-22.25
Step-by-step explanation:
-31.7+4.5(2.1)
-31.7+9.45
-22.25
I think the answer would be D. Hope this helps!
Answer: They are inverses of each other
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Explanation:
We'll need to compute h(f(x)) and f(h(x)) to see if we get x each time.

and,

Both composite functions lead to x each time.
The equations h(f(x)) = x and f(h(x)) = x being true means each function is the inverse of the other.
So, it says x + y = -2
we just plug in the numbers so,
2 + - 4 = -2
This equation is true and can also be written as
2 - 4 = -2
It also then says that 2x - y = 8
Again, you just plug in the numbers
2 * 2 - (-4) = 8
This equation is true and can also be writen as,
2*2 + 4 = 8