Which is equivalent to 7-29i / 8-13i
1 answer:
(7-29i) / (8-13i)=(7-29i)(8+13i)/ (8-13i)(8+13i)=
(56-91i-232i+377i²) / (64-169i²)=
remember:
i=√-1
i²=-1
Therefore:
=(56-141i-377) / (64+169)=(-321-141i) / 233=-(321+141i)/233
Answer: (7-29i) / (8-13i) is equivalent to -(321+141i) / 233
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