Answer:
Carl has 35 dimes and 90 quarters
Step-by-step explanation:
Let the number of quarters be q and the number of dimes be d
Total number of coins is 125;
Hence;
q + d = 125 •••••••••(i)
The total value of quarters present = q * 0.25 = 0.25q
The total value of dimes present = d * 0.1 = 0.1d
Adding both gives the total
0.25q + 0.1d =26 ••••••••(ii)
So we need to solve both equations simultaneously;
From i,
q = 125 - d
Substitute this into ii
0.25(125-d) + 0.1d = 26
31.25 -0.25d + 0.1d = 26
31.25 -26 = 0.25d -0.1d
5.25 = 0.15d
d = 5.25/0.15
d = 35
Recall; q = 125 - d = 125 -35 = 90
You can only multiply numbers that are inside the radical symbols
Note for probability, if it will never happen the P = 0. If it must happen P = 1.
So certain to happen:
C. P=1
Answer:
(7*100) can be written as 7*10^2
4 * / 100 i don’t know
if it was 4 * 100 then it’s 4*10^2
if it was divided then it’s 4*10^-2
8* 1/1000 = 8/1000 = 8*10^-3
add together to get 1.100008 * 10^3 (if it was 4*100)
or 7.00048 * 10^2 ( if it was 4/100)
