Question

Given: g(x) = Square Root of x - 4 and h(x) = 2x - 8. What are the restrictions on the domain of gxh? x is greater than or equal to what?

Answer 1

$g(x) = \sqrt{x - 4}$

$h(x) = 2x - 8$

g x h = $\sqrt{x-4}.(2x-8)$

Looking at the equation we know that there's no way to have a negative root, so we need x - 4 to be greater than or equal to 0

$x - 4 \geq 0$

$x \geq 4$

Answer 2

Answer:

It's 6

Step-by-step explanation: