Given: g(x) = Square Root of x - 4 and h(x) = 2x - 8. What are the restrictions on the domain of gxh? x is greater than or equal

Question

4 years ago

6

to what?

2 answers:

MrRa [10] · Answer 1 · 2022-01-04T08:16:48+03:00

MrRa [10]4 years ago

8 0

$g(x) = \sqrt{x - 4}$

$h(x) = 2x - 8$

g x h = $\sqrt{x-4}.(2x-8)$

Looking at the equation we know that there's no way to have a negative root, so we need x - 4 to be greater than or equal to 0

$x - 4 \geq 0$

$x \geq 4$

Sav [38] · Answer 2 · 2022-01-04T09:34:53+03:00

Sav [38]4 years ago

7 0

Answer:

It's 6

Step-by-step explanation: