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erik [133]
3 years ago
6

Given: g(x) = Square Root of x - 4 and h(x) = 2x - 8. What are the restrictions on the domain of gxh? x is greater than or equal

to what?
Mathematics
2 answers:
MrRa [10]3 years ago
8 0

g(x) = \sqrt{x - 4}

h(x) = 2x - 8

g x h = \sqrt{x-4}.(2x-8)

Looking at the equation we know that there's no way to have a negative root, so we need x - 4 to be greater than or equal to 0

x - 4 \geq 0

x \geq 4

Sav [38]3 years ago
7 0

Answer:

It's 6

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Given:  In parallelogram DEFG,

DH = x + 1

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Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore

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Multiply equation (1) with 3 and then subtract equation (2) from it, we get

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