Solve the system of linear equations by graphing<br> x+y=18<br> y=x+12

Leah has two savings accounts with balances totaling $8,000. She withdrew 15% from one and

DedPeter [7]

Answer:930 Hope this Helps :D

Step-by-step explanation:

For the given problem:

Let the balances of the saving accounts be (x) and (y)

Leah has two savings accounts with balances totaling $8,000

so,

x+y=8000 (1)

She withdrew 15% from one and 40% from the other. If she has $6,350 remaining in the accounts

So, The remaining from the accounts will be (1 - 15%) and ( 1 - 40%)

that will give the decimals: 0.85 and 0.6

so, we can write the following equation:

0.85x+0.6y=6350 (2)

Now, solve the equations (1) and (2) to find (x) and (y)

From equation (1)

y=8000-x (3)

Substitute with (y) from equation (3) into equation (2)

0.85x+0.6*(8000)-x =6350

Now solve the equation

0.85x+0.6*8000-0.6x=6350

0.85x-0.6+4800+6350

0.25x=6350-4800

0.25x=1550

x=6200

Substitute with (x) into equation (3) to find (y)

y=8000-6200=1800

So, the larger account = x = 6200

and the smaller account = y = 1800

Now, we will answer the question, how much money did she withdraw from the account with the larger balance?

so, the answer will be: 15% of x = 0.15 * 6200 = 930

So, the answer will be $930

6 0

1 year ago

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

3 0

3 years ago

I stayed up all night trying to figure out this question but I just can’t

Vilka [71]

Answer:

from what we're given on the drawing, ac and pt are congruent

and from the question format, ab is equal to pq, ac is equal to pr

8 0

2 years ago

Help ill give you Brainliesttt ‼️‼️‼️‼️‼️‼️

Lesechka [4]

Answer:

Step-by-step explanation:

+ we take t- number of tickets and each ticket cost $7.

So t is too the number of people who buy tickets, then

$0\leq t\leq 200$

A) We can calculate the amount of money: M= 7t where $0\leq t\leq 200$

B) The domain for t is $0\leq t\leq 200$ , t is an integer.

C) The range for the amount M:

$0*7\leq M\leq 200*7\\0\leq M\leq 1400$

5 0

2 years ago

2х + y = 20<br> 6x — 5y = 12<br> How do i solve this? This is Systems of equations: Substitution

RideAnS [48]

12819=
Yx ..................................

6 0

3 years ago

Solve the system of linear equations by graphing x+y=18 y=x+12