Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
Answer:
The y-values of equivalent ratios increase at the same rate as their x-values. The vertical distance between points is constant, and the horizontal distance between points is constant. This forms a straight line.
Answer:
Step-by-step explanation:
Answer:
iodine gold mercury
Step-by-step explanation:
9514 1404 393
Answer:
(a) x^2/16 +y^2/9 = 1
Step-by-step explanation:
The form for the equation of an ellipse centered at the origin is ...
(x/(semi-x-axis))^2 +(y/(semi-y-axis))^2 = 1
The vertex values tell you the semi-x-axis is 4 units, and the semi-y-axis is 3 units. Then you have ...
(x/4)^2 +(y/3)^2 = 1
x^2/16 +y^2/9 = 1
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In case you don't remember that form, you can try any of the points in the equations. The equation that works will quickly become apparent.
