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Lerok [7]
3 years ago
13

Describe how to substitute an ordered pair into an equation.

Mathematics
1 answer:
Tatiana [17]3 years ago
5 0
Let's say you have the equation

5x + 3y = 11

You are asked to test the ordered pair (1, 2) to see if it is a solution of the equation. A solution of the equation will make the equation a true statement. The ordered pair (1, 2) has 1 as its x-coordinate and 2 as its y-coordinate.
Substitute 1 for x and 2 for y in the equation. Then work it out to see if it is a true statement.

5x + 3y = 11

5(1) + 3(2) = 11

5 + 6 = 11

11 = 11

Since 11 = 11 is a true statement, the ordered pair (1, 3) is a solution of the equation.
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Thea has a key on her calculator marked $\textcolor{blue}{\bf\circledast}$. If an integer is displayed, pressing the $\textcolor
mel-nik [20]

Answer:

$9$

Step-by-step explanation:

Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.

To find: number that Thea originally entered

Solution:

The final number is $243$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $243$ must be $324$.

As previously the number was squared, so the number before $324$ must be $18$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $18$ must be $81$

As previously the number was squared, so the number before $81$ must be $9$.

6 0
3 years ago
How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?
Lunna [17]

Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

an = 100

Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

n = 50

d = 2

l = ?

Find l

l = a1 + (n - 1)*2

l = 1 + 49*2

l = 99

Sum

Sum = (1 + 99)*50/2

Sum = 2500

The difference and answer is 2550 - 2500  = 50

7 0
3 years ago
Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

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3 years ago
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Step-by-step explanation:

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....

3 0
2 years ago
The mean game scores and standard deviations of four seasons of a football team are given below. Season Mean Standard Deviation
timurjin [86]
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3 years ago
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