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erica [24]
3 years ago
6

During a network infrastructure upgrade, you have replaced two 10 Mbps hubs with switches and upgraded from Category 3 UTP cable

to Category 5e. During the process, you accidentally cut the Cat 5e patch cable that stretches from the network printer to the upgraded switch.
What is the impact on the network?

a) All network nodes authenticated by the same server as the printer will be unavailable.
b) All network nodes connected to the switch will be unavailable.
c) All network nodes, with the exception of the printer, will be available.
d) All network nodes on the same subnet as the printer will be unavailable.
e) All network nodes including the printer will be available.
Computers and Technology
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

The answer is "Option c"

Explanation:

Its the infrastructure used to upgrade, for it's upgrading it begins with improving its internet services, that require new routers, adapters, and modulation schemes, that arrive with smart detectors and functionaries, if it accidentally  cut the cat 5e patch so, all the internet nodes shall be accessible except the server, and wrong choices can be described as follows:

  • In option a, It is wrong because all network is not authenticated by the same server.
  • In option b, Network nodes connection can be a switch, that's why is incorrect.  
  • Option d and Options e both were wrong because it is not divided on the same subnet and the printer is not available for all.
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You need to access the registry on your windows 10 computer how do you do this
Nikitich [7]

Press the Win and R keys together and the Run dialog box will pop up. Type regedit in the dialog box and you will then have access to the registry.

8 0
3 years ago
the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved
gavmur [86]

Answer:

A_{big} = 1143.33cm^2

Explanation:

The given parameters are:

V_{small} = 1080

V_{big} = 1715

C_{small} = 840

Required

Determine the curved surface area of the big cone

The volume of a cone is:

V = \frac{1}{3}\pi r^2h

For the big cone:

V_{big} = \frac{1}{3}\pi R^2H

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

V_{small} = \frac{1}{3}\pi r^2h

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

\frac{H}{h} = \frac{R}{r}

and

\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}

\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}

Substitute values for Vbig and  Vsmall

\frac{1715}{1080} = \frac{R^2H}{r^2h}

Recall that:\frac{H}{h} = \frac{R}{r}

So, we have:

\frac{1715}{1080} = \frac{R^2*R}{r^2*r}

\frac{1715}{1080} = \frac{R^3}{r^3}

Take cube roots of both sides

\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}

Factorize

\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}

\sqrt[3]{\frac{343}{216}} = \frac{R}{r}

\frac{7}{6} = \frac{R}{r}

The curved surface area is calculated as:

Area = \pi rl

Where

l = slant\ height

For the big cone:

A_{big} = \pi RL

For the small cone

A_{small} = \pi rl

Because both cones are similar, then:

\frac{L}{l} = \frac{R}{r}

and

\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}

\frac{A_{big}}{A_{small}} = \frac{RL}{rl}

This gives:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}

Recall that:

\frac{L}{l} = \frac{R}{r}

So, we have:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}

\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2

Make A_{big} the subject

A_{big} = (\frac{R}{r})^2 * A_{small}

Substitute values for \frac{R}{r} and A_{small}

A_{big} = (\frac{7}{6})^2 * 840

A_{big} = \frac{49}{36} * 840

A_{big} = \frac{49* 840}{36}

A_{big} = 1143.33cm^2

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

4 0
3 years ago
Select the focus questions that emphasizes what is more important: (Select all that apply) a.What needs to be relegated to the b
agasfer [191]

Answer:

Options b and d

Explanation:

Option B: What needs to be bigger and more prominent?

This gets the more foucs on the first look of the product to the user. Let's say you are developing a website and in the first page, your name and logo must be prominent and bigger than the rest of the elements on that webpage makes the user remember your name and the business model which gets more focus.

Option D: What needs to be brought into view in the foreground?

As the index says, face is the index of the mind, your product's index page is the face of your product. Hence it should be prioritized to show what is important and what is not.

The above two questions are the most important questions to be considered while emphasizing on what is more important.

5 0
4 years ago
When passing a list of parameters to a stored procedure by name, you can omit optional parameters by:
amm1812

When passing a list of parameters to a stored procedure by name, you can omit optional parameters by omitting the parameter name and value from the list.

<h3>What is optional parameter?</h3>

It should be noted that optional parameter simply means a method that doesn't force pass arguments at calling time.

In this case, when passing a list of parameters to a stored procedure by name, you can omit optional parameters by omitting the parameter name and value from the list.

Learn more about parameter on:

brainly.com/question/13151723

#SPJ12

5 0
2 years ago
Write a function NumberOfPennies() that returns the total number of pennies given a number of dollars and (optionally) a number
Over [174]

Answer:

Following are the code to the given question:

#include <iostream>//header file  

using namespace std;

int NumberOfPennies(int ND, int NP=0)//defining a method that accepts two parameters  

{

return (ND*100 +NP);//use return keyword that fist multiply by 100 then add the value  

}

int main() //main method

{

cout << NumberOfPennies(5,6) << endl; // Should print 506

cout << NumberOfPennies(4) << endl; // Should print 400

return 0;

}

Output:

506

400

Explanation:

In the method "NumberOfPennies" it accepts two parameters that are "ND and NP" that uses the return keyword that multiply 100 in ND variable and add in NP variable and return its values.

In the main method it it uses the cout method that call the by accepts value in parameter and print its value.

4 0
3 years ago
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