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Klio2033 [76]
3 years ago
10

Three of the most important jobs of security management are to ensure _____ are organized according to sensitivity, ensure that

roles maintain _____, and to manage _____ because that is the enemy of security. assets, accountability, software assets, separation of duties, complexity software, separation of duties, complexity software, accountability, people people, separation of duties, technology
Computers and Technology
1 answer:
Leokris [45]3 years ago
4 0

Answer:

separation of duties, accountability, people

Explanation:

Three of the most important jobs of security management are to ensure separation of duties are organized according to sensitivity, ensure that roles maintain accountability, and to manage people because that is the enemy of security.

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Write Album's PrintSongsShorterThan() to print all the songs from the album shorter than the value of the parameter songDuration
lidiya [134]

Answer:

kindly check explainations for code

Explanation:

Check below for program code.

#include <iostream>

#include <string>

#include <vector>

using namespace std;

class Song

{

public:

void SetNameAndDuration(string songName, int songDuration)

{

name = songName;

duration = songDuration;

}

void PrintSong() const

{

cout << name << " - " << duration << endl;

}

string GetName() const { return name; }

int GetDuration() const { return duration; }

private:

string name;

int duration;

};

class Album

{

public:

void SetName(string albumName) { name = albumName; }

void InputSongs();

void PrintName() const { cout << name << endl; }

void PrintSongsShorterThan(int songDuration) const;

private:

string name;

vector<Song> albumSongs;

};

void Album::InputSongs()

{

Song currSong;

string currName;

int currDuration;

cin >> currName;

while (currName != "quit")

{

cin >> currDuration;

currSong.SetNameAndDuration(currName, currDuration);

albumSongs.push_back(currSong);

cin >> currName;

}

}

void Album::PrintSongsShorterThan(int songDuration) const

{

unsigned int i;

Song currSong;

cout << "Songs shorter than " << songDuration << " seconds:" << endl;

/* Your code goes here */

for(int i=0; i<albumSongs.size(); i++){

currSong = albumSongs.at(i);

if(currSong.GetDuration()<songDuration){

currSong.PrintSong();

}

}

}

int main()

{

Album musicAlbum;

string albumName;

getline(cin, albumName);

musicAlbum.SetName(albumName);

musicAlbum.InputSongs();

musicAlbum.PrintName();

musicAlbum.PrintSongsShorterThan(210);

return 0;

}

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Sorry but, what are brainliest for?
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Answer:

smartest and accurate answer

Explanation:

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The answer is D. line graph
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If( c != ' ' )
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Whose job is it to ensure that a group stays focused and on schedule?
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\text{Hello There!}

\text{The job of the facilitator is often to organize group activities.}

\bold{Therefore,\;your \;answer \;is\;going\;to\;be\;A, the\;facilitator.}

\huge\text{I hope this helped! :)}

\rule{250}{1.5}

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