Answer:
Explanation:
The following piece of code is written in Java. It creates the method as requested that takes in two generic objects and compares them using the .equals() built in Java method. This method will return True if the objects are identical or False if they are not. A test case is used in the code and the output can be seen in the attached image below.
public static <T> boolean comparePerez(T a, T b) {
return a.equals(b);
}
Answer:
Jambinai combines Korean folk music instruments and rock music instrumentation, which creates a different music style.
Answer:
1) Yes, Publisher relation should have a publisherID primary key.
2) NOT NULL and UNIQUE for the BookID, BranchID, CardNumber and name of the borrower in the Book, Book_Copies, Library_branch, and Borrower relations respectively. The DueDate field of the book_loan relation must be a time constraint. The BookID of the Book relation must be serial number for automatic addition and update of bookid across the database.
Explanation:
The Publisher relation should have primary key publisherID which should replace the publisherName in the Book relation to easily make a join query and attain a third-level database model.
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The statement "CAPTCHAs can be used as a form of signature to create a valid contract in e-commerce. " is true. It is <span>a program or system intended to distinguish human from machine input, typically as a way of thwarting spam and automated extraction of data from websites.</span>
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
