Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.
Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as:
3c + 4b = 11.33 (1)
Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as:
9c + 5b = 23.56 (2)
<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.
Multiplying equation 1 by three and subtracting equation 2 from it, we get:
3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56
9c + 12b - 9c - 5b = 10.43
7b = 10.43
b = $1.49
Using the value of b in equation 1, we get:
3c + 4(1.49) = 11.33
3c = 5.37
c = $ 1.79
Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.
So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05
Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>
The answer to that is 58,805,595 . hope this helps !!!
Answer:
Below.
Step-by-step explanation:
(a) Over the first 5 seconds rate of change of speed
= (9-1)/5
= 8/5
= 1.6m/s^2
(b) (21-9)/16-t) = 2
12/16-t = 2
32 - 2t = 12
32 - 12 = 2t
20 = 2t
t = 10 seconds
The factors of 28 are 1, 2, 4, 7, 14, and 28.
<span>The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40.
</span>
<span>The common factors are 1, 2, and 4.</span>
