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bearhunter [10]
3 years ago
14

Can you please send me an example for this question (15 ÷ 5 + 6 + 9) x 4 x 2 + 7

Mathematics
2 answers:
Mkey [24]3 years ago
3 0
The answer is 88 hope that helped
podryga [215]3 years ago
3 0
Just remember, do the order PEMDAS = parentheses exponents multiply divide add subtract
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Solve equation for y: -4x+8y=24
Nesterboy [21]
-4x +8y = 24

8y = 24+ 4x
y = 24/8 + 4x/8
y = 3+ x/2

Hope it helps!
#MissionExam001
4 0
3 years ago
Identify the graphed linear equation.<br> A) y=5x+2<br> B) y=5x-2<br> C) y=-5x+2<br> D) y=-5x-2
soldi70 [24.7K]

Answer: y=-5x-2

Step-by-step explanation: If you type all of the options into desmos calculator you will come up with 4 different graphs. Just simply find the graph with your coordinates on it. hope this helped :)

7 0
3 years ago
A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
Is the work shown below correct? Explain your answer.
riadik2000 [5.3K]
(11 + 21) - ( 3 - 100 )
= 32 + 97
= 129

or (11+21)-(3+100)
= 32 - 103
= - 71


I have no idea about your topic but hope it's right! Good luck
8 0
3 years ago
When using base-10 blocks to divide 452 by 2, how many hundreds flats will be in each equal group? hundreds flats Divide 452 by
daser333 [38]
<h3>Given</h3>

4 hundreds flats; 5 tens rods; 2 ones cubes

<h3>Find</h3>

The number of hundreds flats in each of 2 equal piles

<h3>Solution</h3>

When 4 flats are divided into two equal groups, each group will have ...

... 2 flats

_____

You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.

— — — — —

You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.

8 0
3 years ago
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