Green's theorem<span> is what falls out of </span>Stokes<span>' </span>theorem if you restrict it to two dimensions.<span>Stokes’ theorem is a generalization of both of these: given some orientable manifold of an arbitrary dimension, it relates integrals over the boundary of a manifold to integrals over its interior.</span>
For this problem, we are given a parallelogram with a diagonal drawn, inside it there are markings for a few angles. We need to determine the unknown angles.
Opposite sides of a parallelogram are parallel, this means we can treat the diagonal as a transversal line that crosses two parallel lines. Since this is the case, the angles 33º and xº are alternate interior angles and have the same length:

The opposite angles in a parallelogram are congruent, therefore:

The sum of internal angles is 360º, therefore we have:

The value of x is 33º, the value of y is 38º and the value of z is 109º.
I am good with all math from alg-calc
Well to get the area of 288 the dimensions would be a couple of things but 16 ft by 18 ft seems to work, so the dimensions increase by 4 ft on each side.
12+4=16
14+4=18
18*16=288
Answer:
for this graph the answer is D