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3 years ago

6

Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to

her quadratic equation? Round to the nearest tenth if necessary.

2 answers:

daser333 [38]3 years ago

7 0

A = 1
b = -5
c = -4
x1 = 5.70
x2 = -0.70

<span>Therefore, the negative real number is -0.70.</span>

navik [9.2K]3 years ago

5 0

-.7 using quadratic formula to solve

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Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y = – 2x + 5

velikii [3]

Answer:

--2

Step-by-step explanation:

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3 0

3 years ago

Does anybody understand writing equations in slope intercept form?

aleksandr82 [10.1K]

slope intercept form

y=mx+b

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4 0

3 years ago

Read 2 more answers

8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.

loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

$^8C_4\times ^9C_5\times^9C_2\times^7C_3$

$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0

3 years ago

What is the domain of the set of ordered pairs?<br> (8, -13); ( 0,-5); (4, -9); (-3,2)

UNO [17]

The domain is the input values, which are the x values.

The x values in the given pairs are: 8, 0,4,-3

The domain set is (-3, 0, 4, 8)

4 0

3 years ago

Read 2 more answers

P and q are complex numbers such that ∣p∣ = 2/5 x + 2 , ∣q∣ = −3/4 x − 1 , and ∣p+q∣ = 2x + 4 .

Leya [2.2K]

Answer: (b)

Step-by-step explanation:

Given

$\left | p\right |=\dfrac{2}{5}x+2$

$\left | q\right |=\dfrac{-3}{4}x-1$

$\left | p+q\right |=2x+4$

for two complex number, $z_1,z_2$

$\left | z_1+z_2\right |\leq \left | z_1\right |+\left | z_2\right |$

Apply the above the property

$\Rightarrow 2x+4\leq \dfrac{2}{5}x+2-\dfrac{3}{4}x-1\\\\\Rightarrow 2x+4\leq \dfrac{8x-15x}{20}+1\\\\\Rightarrow 2x+3\leq -\dfrac{7x}{20}\\\Rightarrow x\leq -\dfrac{60}{47}$

Also, the absolute value of each complex number must be greater than or equal to zero

$\text{Case-1}\\\\\Rightarrow \dfrac{2}{5}x+2\geq 0\\\\\Rightarrow x\geq -5\\\\\text{Case-2}\\\\\Rightarrow -\dfrac{3}{4}x-1\geq 0\\\\\Rightarrow x\leq -\dfrac{4}{3}\\\\\text{Case-3}\\\\\Rightarrow 2x+4\geq 0\\\Rightarrow x\geq -2$

Taking the intersection of the above values of x, we get

$x\in [-2,-\dfrac{4}{3}]$

8 0

3 years ago