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3 years ago

Perform the indicated opera 6) g(n)= n2 - 1 h(n)= 4n+1 Find (g. h)n)

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

$(g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\$

Step-by-step explanation:

We are given:

$g(n)=n^2-1\\h(n)=4n+1$

We need to find (g.h)(n)

Finding (g.h)(n)

$(g.h)(n)=g(n).h(n)\\ (g.h)(n)=(n^2-1)(4n+1)\\ (g.h)(n)=n^2(4n+1)-1(4n+1)\\ (g.h)(n)=4n^3+n^2-4n-1\\$

So, $(g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\$

Keywords: Composite Function

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Answer:

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3 years ago

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jasenka [17]

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Step-by-step explanation:

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3 years ago

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