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TiliK225 [7]
3 years ago
12

Perform the indicated opera 6) g(n)= n2 - 1 h(n)= 4n+1 Find (g. h)n)

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

(g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\

Step-by-step explanation:

We are given:

g(n)=n^2-1\\h(n)=4n+1

We need to find (g.h)(n)

Finding (g.h)(n)

(g.h)(n)=g(n).h(n)\\ (g.h)(n)=(n^2-1)(4n+1)\\ (g.h)(n)=n^2(4n+1)-1(4n+1)\\ (g.h)(n)=4n^3+n^2-4n-1\\

So, (g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\

Keywords: Composite Function

Learn more about Composite Function at:

  • brainly.com/question/10772025
  • brainly.com/question/4939434
  • brainly.com/question/2723982

#learnwithBrainly

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Step-by-step explanation:

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Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

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<em><u>Hence</u></em><em><u>, </u></em>

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3 years ago
One number is 23 more than another. If the sum of the two numbers is 163, find the two numbers.
kipiarov [429]

ANSWER

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EXPLANATION

We have that one number is 23 more than another.

Let the first number be x.

Let the second number be y.

This means that:

x = 23 + y ____(1)

The sum of the two numbers is 163. This means that:

x + y = 163 ____(2)

Put (1) in (2):

23 + y + y = 163

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x = 23 + 70

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