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-Dominant- [34]
3 years ago
12

Perimeter of rectangle 26ft length 6ft what's the width

Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0
To find the missing width/length for the perimeter of a rectangle:

You multiply the found length/width, in this case, the length, by 2. Since there are 2 of the same sides of a rectangle.
6*2 = 12
Now, you have to subtract the perimeter, 26, from the product.
36 - 12 = 24.
You have to divide the difference by 2 because 24 is the 2 missing sides put together.
24/2 = 12
So, the missing width is 12 feet.

From,
Loafly
trasher [3.6K]3 years ago
4 0
The answer would be 20
I know this because if the entire rectangle is 26 and the length is 6 then subtract 26 and 6and your answer is 20. I hope this was helpful!!!
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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

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The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

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2 years ago
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Step-by-step explanation:

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I can't tell if that is a question but I will answer it anyway:

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3 years ago
A card is selected randomly from a jar that contains 15 cards, numbered from 25 to 39. What is the probability that the card sel
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Answer:

The probability that the card selected bears a number less than 34 is 0.3333.

Step-by-step explanation:

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The number on the cards are as follows:

S = {25, 26, 27,..., 38, 39}

The probability of an event, <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

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In this case we need to compute the probability that the card selected bears a number less than 34.

The favorable outcomes are:

<em>s</em> = {25, 36, 37, 38, 39}

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Compute the probability that the card selected bears a number less than 34 as follows:

P(X

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Thus, the probability that the card selected bears a number less than 34 is 0.3333.

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