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mina [271]
4 years ago
13

What is the volume of a right circular cylinder with a radius of 4 m and a height of 4 m?

Mathematics
2 answers:
katovenus [111]4 years ago
7 0

Answer:

V≈201.06m³

Step-by-step explanation:

V=πr2h=π·42·4≈201.06193m³

plz mark me as brainliest if this helped :)

liraira [26]4 years ago
7 0

Answer:

16 m

Step-by-step explanation:

i had the same quiz

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Triangle X Y Z is shown. The length of side X Y is (9 n + 12) feet and the length of side X Z is (15 n minus 6) feet. Angles X Y
zmey [24]

Answer:

n = 3

XY = 39

XZ = 39

Step-by-step explanation:

Given

XY = 9n + 12

XZ = 15n - 6

Solving (a): n

To solve for n;

We make use of

XY = XZ

Substitute values for XY and XZ

9n + 12 = 15n - 6

9n - 15n = -12 - 6

-6n = -18

Divide through by -6

n = 3

Solving (b) XY

XY = 9n + 12

Substitute 3 for n

XY = 9 * 3 + 12

XY = 27 + 12

XY = 39

Solving (c): XZ

XZ = XY

XZ = 39

7 0
3 years ago
Nina graphs the function y=⌊x⌋ to learn the properties of the parent floor function.
BabaBlast [244]

Answer:

  5

Step-by-step explanation:

For positive numbers, the floor function y = ⌊x⌋ gives the integer portion of the number.

  ⌊5.7⌋ = 5

5 0
3 years ago
Help help help pelesss please
blagie [28]

Answer:

its 1

Step-by-step explanation:

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8 0
3 years ago
Need help<br><br><br>y+3=6(x+2)-3
olga_2 [115]

<u>Slope-Intercept:</u>

y + 3 = 6(x + 2) - 3

y + 3 = 6x + 12 - 3

<u>     -3 </u>   <u>             -3 </u>

y        = 6x + 12

<u>Standard:</u>

       y = 6x + 12

<u>-6x </u>       <u>-6x        </u>

-6x + y = 12

-1(-6x + y = 12)

  6x - y = -12

<u>Graph:</u>

y = 6x + 12

      ↓      ↓

      ↓     y-intercept

   slope

Start by graphing the y-intercept: (0, 12)

Then count the rise (up 6) and the run (right 1) from the y-intercept: (1, 18)

or

count the rise (down 6) and the run (left 1) from the y-intercept: (-1, 6)

4 0
3 years ago
Pls help need asap I’m stressing so much it would<br> Mean a lot just to help out I’ve been waiting
Troyanec [42]
The answer she be (6, 0.5)
4 0
3 years ago
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