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Amanda [17]
3 years ago
6

1) There are 32 chocolates in a box, all identically shaped. There are 9 filled with nuts, 11 with caramel, and 12 are

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

answer

\frac{33}{248} ≈ 0.1331 = 13.31 %

first chocolate

the probability of picking a chocolate the first time is \frac{solid chocolates}{total chocolates}

there are 12 solid chocolates and 32 total chocolates

\frac{solid chocolates}{total chocolates} = \frac{12}{32} = \frac{3}{8}

second chocolate

the probability of picking a chocolate the first time is \frac{solid chocolates}{total chocolates}

since we already picked a solid chocolate the first time, there is one less solid chocolate and one less total chocolate

there are 12 - 1 = 11 solid chocolates and 32 - 1 = 21 total chocolates

\frac{solid chocolates}{total chocolates} = \frac{11}{31}

total probability

to find the probability of both being solid chocolates, multiply their individual probabilities together

\frac{3}{8} *\frac{11}{31}

= \frac{3 * 11}{8 * 31}

= \frac{33}{248}

≈ 0.1331

= 13.31 %

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