Which expression is equivalent to 4a + 10?
2 answers:
Answer:
The equivalent expression of the given expression is 2(2a+5).
Step-by-step explanation:
The given expression is
The factors of given terms are
The common factor is 2. Take out the common factor from each term.
Therefore the equivalent expression of the given expression is 2(2a+5).
Answer:
which is equivalent expression.
which is equivalent expression.
Step-by-step explanation:
The equivalent expression is the expression which will maintain the symetry of the expression will not change the expression.
We have been given the expression:
Now, the maximum simplified form of this expression is
we can divide the each term by 4 we will get:
which is equivalent expression.
or we can divide each term by 10 we get:
which is equivalent expression.
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2 1/2 + 4 1/4 = 6 3/4
6 3/4 = 27/4
So Naomi earned $8 per hour that she mows the lawn.
6 3/4 = 27/4
So Naomi earned $8 per hour that she mows the lawn.
Answer:
6
Step-by-step explanation:
If the question were how many distinct four digit number contain the digits 1,2,3, and 4 without repetition we could use the variation without repetition formula for 4 elements.
The first digit must be any of this four digits, so, we have 4 possibilities.
For the second digit, we already used one digit, so, we only have 3 possibilities. The total possibilities of picking this first two numbers are 4 * 3.
For the third digit, we already used two digits, so, we have 2 possibilities. The total possibilities thus far are then 4 * 3 * 2.
And for the final digit we don't have a choice, its the only one left. So we have 4 * 3 * 2 * 1 possibilities for a four digit number formed by the digits 1,2,3, and 4 without repetition .
This number its the factorial of 4:
.
If the digit 2 is always immediately followed by the digit 3, no, we don't have 4 choices, cause, our elements are:
the digit 1 , the duple 2 3 , and the digit 4
So, for the first position, we must choose one of this elements. Lets say 1.
1 _ _ _.
Then, we can choose the duple 23 for the second and third position:
1 2 3 _
Finally we only got one choice, the digit 4:
1 2 3 4
So, as we can see. This is the same that choosing three elements without repetition. The possibilities will be:
.
Now, we could: ask which are this possibilities?. They are:
1 2 3 4
1 4 2 3
2 3 1 4
2 3 4 1
4 1 2 3
4 2 3 1