Answer:
Step-by-step explanation:
to solve this problem we can use the Pythagorean theorem
UT and TL are the legs, while LU is the hypotenuse
We have to find LU so we can proceed like this
x^2 + (x+1)^2 = LU^2
x^2 + x^2 + 1 + 2x = LU^2
2x^2 + 2x + 1 = LU^2
LU = +/- 
we have to take only the positive value because a length can’t be negative.
2x^2 + 2x + 1 is positive for every value of x, so the final answer is

[x-(-10)]²+(y-6)²=4²
the answer is (<span>x + 10)^2 + (y – 6)^2 = 16</span>
Answer:
im just trying to get points
Step-by-step explanation:
Answer:
\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]
Step-by-step explanation:
Given is a matrix 3x3 as
![\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%262%5C%5C-3%261%264%5C%5C2%26-3%264%5Cend%7Barray%7D%5Cright%5D)
|A| =2 hence inverse exists.
Cofactors are 16 20 7
6 8 3
2 2 1
Hence inverse =
![\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%266%262%5C%5C20%268%262%5C%5C7%263%261%5Cend%7Barray%7D%5Cright%5D)