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3 years ago

What makes "24" using the numbers "4 4 6 5"

Mathematics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

4 and 6

Step-by-step explanation:

4 and 6

MA_775_DIABLO [31]3 years ago

5 0

Using those numbers u can use 5 times 4+4

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In AABC, MLA = 53, m4C = 84, and side a = 8 inches. Find the length of side b to the nearest tenth of an inch.

Cerrena [4.2K]

Answer:

6.8 inches

Step-by-step explanation:

Given data :

m∠ A = 53° , m∠ C = 84° , side a = 8 inches

therefor m ∠ B = ( 180 - (84 + 53 )) = 43°

Find the length of side b

we will apply sine rule here

$\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}$

= $\frac{8}{sin53}$ = $\frac{b}{sin43}$

∴ b = ( sin43° * 8 ) / sin53°

= ( 0.6819 * 8 ) / 0.7986

= 5.4552 / 0.7986 = 6.83 ≈ 6.8 inches

8 0

3 years ago

Phantasy [73]

Answer:

To find the slope of a line, divide the change in x by the change in y

Step-by-step explanation:

You divide the change in y over the change in x.

5 0

2 years ago

Evalua 6+x cuando x=3

Gala2k [10]

Answer:

6+3=9

Step-by-step explanation:

Evaluando 6+3=9, porque tu tienes que intercambiar x por 3 porque x es 3. Después tu tienes que buscar tu repuesta. Disculpa mi español no es tan bueno escribiendo

6 0

3 years ago

For what side length(s) is the area of an equilateral triangle equal to 30 cm?? Only enter the number, in centimeters, rounded t

xenn [34]

Answer: The sides length are 8.32 cm

Step-by-step explanation:

An equilateral triangle has all his sides of the same lenght, so we assume that the triangle has an L lenght in his sides.

The area of a triangle is $Area = \frac{base * height}{2}$ where the base is L, the Area is 30 and an unknown height.

To determine the height, we cut the triangle in half and take one side. By simetry, one side has a base of $\frac{L}{2}$ , a hypotenuse of L and a the unknown height.

Then we apply the Pythagoras theorem, this states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, or, $hypotenuse = \sqrt{c^{2} + c^{2} }$ Where one c is $\frac{L}{2}$ and the other is the height.