(0, 5) is the minimum value.
Find the axis of symmetry by plugging the respective variables into -b/2a
-5/2(0) = 0
There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as
y = 2x^2 + 0x + 5
We plug 0 into f(x), establishing every x-value as 0.
f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5
5 is now your vertex’s y-value. Plot the two values together.
(0, 5)
We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.
Answer:
-4
Step-by-step explanation:
Rewrite 16 as 4 squared
Pull terms out from under the radical, assuming positive real numbers
-1 x 4
Then you get the answer -4
Solve for w by simplifying both sides of the equation, then isolating the variable.
w=13
28°
a triangle = 180°
180°-140°= 40°
180°-68°= 112°
180°-112°-40°= 28°
Answer: 1.333333333333333333334
