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Nadya [2.5K]
3 years ago
13

Write one hundred and fourteen thousandths as a decimal number.

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

100.014. I think this is it

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The profits in hundreds of dollars, p(c), that a company can make from a product is modeled by a function of the price, c, they
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Answer:

640,000

Step-by-step explanation:

took test

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2 years ago
NEED HELP PLEASE<br> will mark brainliest
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Answer:

we have to find the quotient and the remainder when (x³ + 5x + 3x² + 5x³ + 3) is divided by (x² + 4x + 2) ♥9 dividend = x² + 4x + 2 using Euclid division lemma, x² + 4x + 2) x² + 5x³ + 3x² + 5x + 3(x³ - 4x² + 19x - 65 x² + 4x² + 2x³ - 4x² + 3x² + 3x² - 4x*-16x³8x² 19x³ + 11x² + 5x 19x³ +76x² + 38x -65x²-33x + 3 -65x²-260x - 130 +227x + 133 Therefore the quotient is x² - 4x + 19x - 65 and remainder is 227x + 133

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2 years ago
What is <br> 1/5 * 1/6x = - 33
azamat

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7 0
3 years ago
Read 2 more answers
WORTH 20 PTS!!!
Rama09 [41]
For this case we have the following function:
 A (t) = A0e ^ {(kt)}&#10;
 Where,
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 t: time in years
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 A (t) = 22000 * e ^ {(- 0.021 * t)}&#10;
 For the year 2015 we have:
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the predicted population in 2015 is:
 
19,807
7 0
3 years ago
use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

Yes, this equation has a solution. According to Intermediate Value Theorem at least one solution for [0,2]

Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

2) The Intermediate Value Theorem can be applied to determine whether there is a solution on a given interval.

Let's choose the interval [0,2]

f(x)=x^{3}-3x-1\\f(0)=(0)^{3}-3(0)-1\\f(0)=-1\\f(0)

Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

3 0
3 years ago
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