If you use a 0.10 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting a null hypothesi
s that the population mean equals 500 if you use the Z test
1 answer:
Answer:
Our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.
Step-by-step explanation:
The hypotheses would be;
Null hypothesis;H0: μ = 500
Alternative hypothesis;Ha: μ ≠ 500
Since it's two - tailed at 0.1 level of significance, then each tail will contain 5% or 0.05. From the z-table attached, the corresponding critical value of 0.05 is approximately 1.645 standard deviations from the mean.
Thus, our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.
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Answer:
(a) 6.2843 billion
(b) 6.8716 billion
Step-by-step explanation:
Since there is a constant growth rate of 1.5% per year, and the population in 2002 was 6.1 billion people. The general equation for the total world population, in billions, after 2002 is:
With t being the time, in years, after 2002.
a) What was the population in 2004?
b) What was the population in 2010?
Answer : option d
4.4, 5.8, 7.2, 8.6, 10, …
First we find the common difference between two terms
5.8 - 4.4 = 1.4
7.2 - 5.8 = 1.4
8.6 - 7.2 = 1.4
10 - 8.6 = 1.4
So common difference is 1.4
To find recursive rule, we add the difference with previous term
Recursive rule is
a1 is the first term so a1= 4.4
d is the difference = 1.4
So recursive rule is
, where a1 = 4.4