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Sati [7]
4 years ago
13

If you use a 0.10 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting a null hypothesi

s that the population mean equals 500 if you use the Z test

Mathematics
1 answer:
Dovator [93]4 years ago
7 0

Answer:

Our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

Step-by-step explanation:

The hypotheses would be;

Null hypothesis;H0: μ = 500

Alternative hypothesis;Ha: μ ≠ 500

Since it's two - tailed at 0.1 level of significance, then each tail will contain 5% or 0.05. From the z-table attached, the corresponding critical value of 0.05 is approximately 1.645 standard deviations from the mean.

Thus, our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

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Answer:

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Answer:

-5/ (x^19 * y^12)

Step-by-step explanation:

-15x^-10 * y ^ -3 * x^-9 * y^-9/3 (It's writing it like this.)

15 and 3 have a GCF of 3.

-5x^-10 * y^-3 * x^-9 * y^-9/1

Reduce similar occurrences. *twice in a row*

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Negative powers change multiplication to division.

-5 / (x^19 * y^12) is the final answer.

Even with that, the simplified answer wouldn't have negative exponents because of the negative powers rule.

8 0
3 years ago
HELP ME ASAP!!! PLEASE
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B, 190.
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Sorry if it's wrong.

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