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3 years ago

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prove that the sum of two consecutive exponents of the number 5 is divisible by 30. If N ia the smaller of two consecutive expon

ents, then the sum of two consecutive exponents of 5 is equal to _ *30, and therefore is divisible by 30.

1 answer:

kotykmax [81]3 years ago

3 0

Answer:

5^n-1

Step-by-step explanation:

5^n-1*30

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muminat

Answer:

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Step-by-step explanation:

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2 years ago

I need help on this

Komok [63]

Answer:

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Step-by-step explanation:

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3 years ago

cestrela7 [59]

Answer:

A. -18·10^6

Step-by-step explanation:

The rules of exponents apply to powers of 10 used in scientific notation. The associative and commutative properties of multiplication also apply.

<h3>Application</h3>

(a^b)(a^c) = a^(b+c)

The numerical product is ...

$(9\cdot10^9)\cdot(-2\cdot10^{-3})=(9)(-2)(10^{9-3})=\boxed{-18\cdot10^6}$

__

<em>Additional comment</em>

Expressed in scientific notation, the result would be ...

$-1.8\cdot10^7$

Your calculator can perform this multiplication for you.

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2 years ago