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3 years ago

Can someone help me plz

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

Answer:

i got 85

Step-by-step explanation:

Alex777 [14]3 years ago

3 0

The answer to this question is 82

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Help pleaseeeeeee :(

Vikki [24]

Answer:

Do 16 times pi.

Step-by-step explanation:

The closest answer is D.

5 0

2 years ago

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Why is 1/3 greater than 1/6

Korvikt [17]

Because 1/3 is equal to 2/6 which is greater than 1/6

3 0

2 years ago

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Which statements are true about a rectangular pyramid with a height of 9 centimeters and a base with the dimensions of 4 centime

Evgesh-ka [11]

Answer:

I did not get this one right, but I will tell you that I know a lot of people, including me who put:

B and D.

Those two together are NOT right. and the other question I got wrong was number 5. That answer is not D. So don't put that. Everything else, I got correct.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

Graph the inequality. -8 < y + 2x < 14

kap26 [50]

Answer:

Step-by-step explanation:

Split it into 2 inequalities:

-8 < y + 2x

y + 2x < 14

Isolate y , subtract 2x from first and then from second

-8 -2x < y

y < 14 -2x

Rewrite it so it looks pretty?

y > -2x-8

y < -2x +14

You can use the calculator to graph each inequality.

The solution or the system is the area where the 2 solutions for each line overlap.

7 0

2 years ago