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lesya [120]
3 years ago
9

2k + 10 distributive princess property

Mathematics
1 answer:
Anton [14]3 years ago
7 0
Here you go
2•k+10
(10•k)+(10•2)
is that in the answers? If not, do not put it in!
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Find the surface area of the net below.
Hatshy [7]

Answer:

okay so first to find the surface area of the net below you should always start from the line that is pointing at the end of the the i n u m so you see that is between 8 1/8 and 2 so you see the line you draw a line in the middle between 8 and then when you look and then you draw another line were 19 years and then you draw another line so you can see that at the top of 19 and there at the bottom of 918 you see that you can find the Nets below because you can see me you draw your line it shows you Drawing the Line because when you draw a circle in the middle and then you draw a another little circle in the middle is shows the surface area of the net below so bye

5 0
3 years ago
Write 23 in scientific notation A. 23 x 101 B. 2.3 x 101 C. 2.3 x 102 D. 2.3 x 103
miskamm [114]
When using scientific notation, you only want one number to be in front of the decimal place. If you have to make the number smaller, then the 10^nth power will be positive. If you have to make the number bigger, then 10^nth power will be negative. Example:
0.54 --> 5.4 * 10^-1
35 --> 3.5 * 10^1
The value of n depends on how many spaces the decimal point needs to be moved. For your question, putting 23 in scientific notation would look like this:
23 --> 2.3 * 10^1
8 0
3 years ago
Read 2 more answers
The American Airlines Stock Drop $12 in 6 hours . how much money did it drop per hour ?
Arisa [49]

Answer:

$2 per hour

Step-by-step explanation:

12 / 6 = 2

7 0
3 years ago
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Write the product in standard form (2x + 5) ^2
Iteru [2.4K]

Answer:

4x^2+20x+25

Step-by-step explanation:

(2x+5)^2 = (2x+5) (2x+5)

Using the foil method : 2x(2x) = 4x^2

(2x) (5) = 10x

(2x) (5) = 10x

5 (5) = 25

Combine like terms

4 0
3 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
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