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3 years ago

How many diagonals can be drawn from each vertex of a 16-gon?

Mathematics

1 answer:

olchik [2.2K]3 years ago

7 0

The answer may be 30

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In a class of 30 students, 12 have a cat and 19 have a dog. There are 6 students who

Anna007 [38]

Answer:

19/30

Step-by-step explanation:

30 students

12 have cat , 19 have dog , 6 no cat or dog

P dog = 19 have dogs/30 students total = .633333...

7 0

3 years ago

Convert 0.2146666 into fraction in its simplest form

Lana71 [14]

Answer:

1073333/5000000

Step-by-step explanation:

To convert from decimal to fraction : take denominator as 10000000.

2146666/10000000

1073333/5000000

4 0

2 years ago

Read 2 more answers

A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored

dem82 [27]

Answer:

Mutually exclusive,

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

$P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}$

$P(\text{Lemon-lime})=\frac{4}{12}$

$P(\text{Lemon-lime})=\frac{1}{3}$

Let us find probability of finding one orange drink.

$P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}$

$P(\text{Orange})=\frac{4}{12}$

$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

$P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}$

$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

8 0

3 years ago

On a separate sheet of paper, graph the system of inequalities and highlight the solution. Determine whether (4,5) , (7,6) and (

Bumek [7]

Answer:

is not, not enough money earned

is, enough money earned within the allowed hours.

is not, too many hours worked

Step-by-step explanation:

6 0

3 years ago

Im lost How to solve it

Firlakuza [10]

The answer to this question is:

9x+8/3x^2

6 0

3 years ago