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MrRissso [65]
2 years ago
8

Line GH passes through points (2, 5) and (6, 9). Which equation represents line GH?

Mathematics
2 answers:
boyakko [2]2 years ago
8 0
I'm pretty sure that the equation is y=x+3

If you ever need help finding out the equations of given points on a graph (or plotting one) go to https://www.desmos.com/calculator. It helped me a lot
oksano4ka [1.4K]2 years ago
8 0

Answer:

The equation that represent the line GH is:

y = x + 3

Step-by-step explanation:

If we have two point of a line, we can calculate the equation that represent the line using the following equation:

y-y_1=m(x-x_1)

Where m is equal to:

m=\frac{y_2-y_1}{x_2-x_1}

Additionally, the first point have the form (x_1, y_1) and the second point have the form (x_2,y_2).

Then, replacing the values of x_1 by 2, y_1 by 5, x_2 by 6 and y_2 by 9, we get:

m=\frac{9-5}{6-2}=1

Replacing the value of m and solving for y, we get:

y-5=1(x-2)\\y-5=x-2\\y=x-2+5\\y=x+3

So, the equation that represent Line GH is:

y = x + 3

That means that every point of the line GH have the following form:

( x , y ) = ( x , x+3 )

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Bob makes three different silverware - spoons, forks and knives. Each unit (dozen) of spoon gives him a profit of $9, forks of $
Gala2k [10]

Answer:

Solution is:

z  (max) = 687.5

x₁   =  0

x₂   = 16

x₃   = 21

Step-by-step explanation:

From the problem statement we have:

Resources:      machine time ( 183 h)      labor (250  h)   steel  185 (pounds)

Unit

Spoons                          4                                     4                          3

forks                               4                                     9                          2

knives5                          5                                     5                          4

Profit $                           9                                    20                       17.5

Objective function z =  9*x₁  +  20*x₂  + 17.5 *x₃   to maximize

Subject to:

Availability of machine time  :  183 h

4*x₁  +  4*x₂ +   5*x₃ ≤  183

Availability of labor  :  250 h

4*x₁  +  9*x₂  +  5*x₃  ≤  250

Availability of steel  :  185 pounds

3*x₁  +  2*x₂  +  4*x₃  ≤  185

Requirement:

x₂ ≥ 16

General constraints:

x₁  ≥ 0             x₃      ≥  0 all integers

After 6 iteration the solution using AtomZmath on-line solver

z  (max) = 687.5

x₁   =  0

x₂   = 16

x₃   = 21

Resources used:

Machine time: 16* 4 + 21*5  =  64  +  105  = 169

remains   183 - 169  = 14 h

Labor:  16*9  +  21* 5  =  144  +  105  =  249

remains   250 -  249  =  1 h

Steel :  16*2  +  21*4  =  32  + 84  =  116

remains   185  -  116  = 69 pounds.

If it is decided that 20 units of forks are to be made then

we will need   4*4 = 16   h of machine time

                         9*4 =  36 h  of labor

                         2*4 = 8 pounds of steel

We can get that from abandom to make one unit of x₃ ??

No because as we said we need 36 hours  of  labor ( we still have 1 we need 35 more hours ) if we make 20 x₃ insted of 21 we get only 5 hours.

z we got is maximum

5 0
3 years ago
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