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vichka [17]
3 years ago
10

Helppp please I need help with this ASAP

Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

-7 < -5

Step-by-step explanation:

-5 is greater than -7

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How many different triangles can you make with the following conditions: angles measuring 45 degrees and 90 degrees and an INCLU
kotykmax [81]

Answer:

One

Step-by-step explanation:

Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)

To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.

Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.

3 0
3 years ago
Solve for x in the equation X^2 - 8X + 41= 0
BaLLatris [955]

Answer:

The equation has two solutions for x:

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

Step-by-step explanation:

Let's use the quadratic formula for solving for x in the equation:

X^2 - 8X + 41= 0

x² - 8x + 41 = 0

Let's recall that the quadratic formula is:

x = -b +/- (√b² - 4ac)/2a

Replacing with the real values, we have:

x = 8 +/-  (√-8² - 4 * 1 * 41)/2 * 1

x = 8 +/-  (√64 - 164)/2

x = 8 +/-  (√-100)/2

x = 8 +/-  (√-1 *100)/2

Let's recall that √-1 = i

x = 8 +/- 10i/2

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

8 0
3 years ago
The value of a in the equation ax + y = 5 , if x = 2 and y = 3 is a) – 1 b) 0 c) 1
sasho [114]

Answer:

c) 1

Step-by-step explanation:

=> ax+y = 5

<u><em>Putting x =2, y =3</em></u>

=> a(2)+3 = 5

=> 2a = 5-3

=> 2a = 2

<em>Dividing both sides by 2</em>

=> a = 1

3 0
3 years ago
Read 2 more answers
Evaluate ab + 3c when a=-6, b=-2, and c=5
ra1l [238]
Do it step by step
ab+3c
(-6)(-2)+3(5)
A negative times a negative is positive. (-)(-)=+
12+3(5)
12+15
=27
8 0
3 years ago
Please help me with these two math questions!!
Westkost [7]

Answer:

the answer would be 1/6

Step-by-step explanation:

The reason for this is because 1/12 if you simplify 1/12 you would get 1/6. the number 2 is the same answer

5 0
3 years ago
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