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lesantik [10]
3 years ago
14

The baseball team is purchasing 10 hot dogs, 4 hamburgers, and three loaded nachos. The snack bar will cover 60% of the cost for

the team. The 12 players on the team are equally responsible for the rest of the cost. How much will each member owe? (Hot Dogs cost $1.65, Hamburgers cost $4.50, and Loaded Nachos Cost $3.75) It also helps if you can explain how you did your answer.
*I NEED 2 UNDERSTAND*
Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

1.50

Step-by-step explanation:

X = hot dog price

Y = hamburger price

5X + 4Y = 16.50

4X + 5Y = 17.25

4(5X + 4Y = 16.50)

20X + 16Y = 66

5(4X + 5y = 17.25)

20X + 25Y = 86.25

Now subtract the equations:

20X + 16Y = 66

20X + 25Y = 86.25

9Y = 20.25

Y = 2.25

Hamburger is $2.25

4X + 5(2.25) = 17.25

4X + 11.25 = 17.25

4X = 6.00

X = 1.50

Hamburgers are $2.25

Hotdogs are $1.50

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43.25

Step-by-step explanation:

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Find the value of x , if log₂ [log₅ (log₃x)] = 0
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\log_2 (\log_5( \log_3x)) = 0\\
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3 0
3 years ago
Y=x-4 y=4x+2<br> whats the solution of system equations
Fittoniya [83]

Answer:

X=-2

Y=-6

Step-by-step explanation:

Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence

x-4=4x+2

Bringing like terms together

-4-2=4x-x

Solving both sides

-6=3x

Making x the subject then

X=-6/3=-2

Subsrituting the value of x into any of the initial equations

Y=x-4 then y=-2-4=-6

Therefore, the solution is

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6 0
2 years ago
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
If the original price of pair of pants is $40 and they are on sale for $28. What is the percent discount?
vazorg [7]

Answer:

7.2

Step-by-step explanation:

the original is 40 and discount is 28% so $40-28%

6 0
3 years ago
Read 2 more answers
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