Question

D(n)= 16 5 ​ (2) n−1

Answer 1

Answer:

See explanation

Step-by-step explanation:

Assuming you want to find the 3rd term of the geometric progression defined explicitly by $d(n)=165(2^{n-1})$, then we have to substitute n=3 to obtain:

$d(3)=165(2^{3-1})$

This will give us:

$d(3)=165(2^2)$

We evaluate to obtain:

$d(3)=165\times4=660$