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3 years ago

D(n)= 16 5 (2) n−1

Mathematics

1 answer:

Dmitrij [34]3 years ago

7 0

Answer:

See explanation

Step-by-step explanation:

Assuming you want to find the 3rd term of the geometric progression defined explicitly by $d(n)=165(2^{n-1})$ , then we have to substitute n=3 to obtain:

$d(3)=165(2^{3-1})$

This will give us:

$d(3)=165(2^2)$

We evaluate to obtain:

$d(3)=165\times4=660$

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Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

D(n)= 16 5 ​ (2) n−1

D(n)= 16 5 (2) n−1