400 because I said so and u are asking me is here is the answer
Answer: b is the answer
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Step-by-step explanation:
i did the quiz
The matrix that represents the matrix D is ![\left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
<h3>How to determine the matrix d?</h3>
Given the elements of the matrix C.
The matrix c is represented by its rows and columns element, and the arrangements are:
C11 = 3 C12 = 1 C13=-9 C14 = 8
C21 = 2 C22=2 C23 =0 C24 = 5
C31 = 16 C32 = 1 C33=-3 C34=11
Remove the matrix name and position
3 1 9 8
2 2 0 5
16 1 -3 11
Represent properly as a matrix:
![C = \left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
Matrix C equals matrix D.
So, we have:
![D = \left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
Hence, the matrix that represents matrix D is ![\left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
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Answer:
C. 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x + 1
x + 3y = 10
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: x + 3(2x + 1) = 10
- Distribute 3: x + 6x + 3 = 10
- Combine like terms: 7x + 3 = 10
- [Subtraction Property of Equality] Subtract 3 on both sides: 7x = 7
- [Division Property of Equality] Divide 7 on both sides: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = 2x + 1
- Substitute in <em>x</em>: y = 2(1) + 1
- Multiply: y = 2 + 1
- Add: y = 3
<u>Step 4: Find difference</u>
y = 3
x = 1
- Subtract: 3 - 1 = 2