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wariber [46]
3 years ago
12

Please help. I don't know how to answer this.

Mathematics
1 answer:
Allisa [31]3 years ago
3 0
 the train route (5,13)
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The sign of the product of –35 and –625 is (positive, negative, zero)
ziro4ka [17]

Step-by-step explanation:

-35 x - 625 = 21875 so positive

263 x 0 = 0 so zero

-21 x 451 = - 9471 so negative

-350 x 89 = - 31150 so negative

3 0
3 years ago
Read 2 more answers
In Problems 23–30, use the given zero to find the remaining zeros of each function
Talja [164]

Answer:

x =  2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

f(x) = x^3 - 4x^2+ 4x - 16

One of the zeroes of the above polynomial is 2i, that is :

f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0

Thus, we can write

(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Now, we check if -2i is a root of the given polynomial:

f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0

Thus, we can write

(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Therefore,

(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Dividing the given polynomial:

\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4

Thus,

(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

X = 4 is a root of the given polynomial.

f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0
3 years ago
Find the geometric mean of 125 and 5
kramer

Answer:

25

Step-by-step explanation:

7 0
4 years ago
From data gathered in the period 2008−2012, the yearly value of U.S. exports can be modeled by the function E(x) = −228x3 + 2,25
tester [92]

Answer:you got this:)

Step-by-step explanation:

5 0
3 years ago
B Identify the coefficient and the number of terms in the
Elenna [48]
It’s D because the number that have an (x) is a COEFFICIENT and I hope it helps :)
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