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Hoochie [10]
3 years ago
13

What is the square root

Mathematics
1 answer:
shusha [124]3 years ago
4 0

Answer:

Step-by-step explanation:

Trying to factor as a Difference of Squares :

1.1      Factoring:  r2-96

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 96 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  1  :

 r2 - 96  = 0

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    r2-96 = 0

Add  96  to both sides of the equation :

                     r2 = 96

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     r  =  ± √ 96  

Can  √ 96 be simplified ?

Yes!   The prime factorization of  96   is

  2•2•2•2•2•3

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 96   =  √ 2•2•2•2•2•3   =2•2•√ 6   =

               ±  4 • √ 6

The equation has two real solutions  

These solutions are  r = 4 • ± √6 = ± 9.7980  

Two solutions were found :

                  r = 4 • ± √6 = ± 9.7980

Processing ends successfully

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How would the expression x^3-8 be rewritten using difference of cubes ​
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(x - 2)(x² + 2x + 4)

Step-by-step explanation:

A difference of cubes factors in general as

• a³ - b³ = (a - b)(a² + ab + b² )

note 8 = 2³ = 8 ⇒ b = 2 , with a = x

Hence

x³ - 8

= x³ - 2³

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What makes an equation with an inequality symbol true?
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Answer:

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Step-by-step explanation:

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3 years ago
find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

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x/-2= (y+5)/2

-x=y+5

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