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ArbitrLikvidat [17]
3 years ago
6

How are addition properties and subtraction rules helpful when solving problems

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0
For the sum we have the following properties:
 The properties are commutative, asosiative, distributive and neutral element.

 Commutative property: When two numbers are added, the result is the same regardless of the order of the addends.

 Associative property: When three or more numbers are added, the result is the same regardless of the order in which the addends are added.

 Neutral element: The sum of any number and zero is equal to the original number.

 Distributive property: The sum of two numbers multiplied by a third number is equal to the sum of each summand multiplied by the third number.<span><span>

 </span><span>For subtraction we have:
 
</span><span> The arithmetic operation of the subtraction (subtraction) is indicated by the minus sign (-) and is the opposite, or inverse, operation of the addition. </span><span>That is, it is an arithmetic operation that serves to find the difference between two numbers.
</span><span> 
 In subtraction A - B = D
 </span><span>A is the minuendo
 </span><span>B is the substraendo
 </span><span>D is the difference

 </span><span>Answer:
 </span><span>The properties of addition and subtraction serve to rewrite and simplify calculations.</span></span>
Oduvanchick [21]3 years ago
8 0
The addition and subtraction properties include four mathematical properties:commutative property, associative property, identity property and inverse operations. These properties are helpful in solving problems, because they help to regroup numbers so at the end you will have an easier and simpler equation to solve.  
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Step-by-step explanation:

For example, subtract 56 by 47, you get 9. Each term is 9 more than the previous term.

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Sergio consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Sergio's bod
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Read 2 more answers
9. Triangle Construction pays Square Insurance $5,980
xxTIMURxx [149]

The triangle pay $32 more for that day than it paid per day during the first period of time.

Step-by-step explanation:

The given is,

              Triangle Construction pays Square Insurance $5,980

               To insure a construction site for 92 days

               To extend the  insurance beyond the 92 days costs $97 per day

               Triangle extends the insurance by 1 day

Step:1

              Insurance per day from the 92 days period,

                                                                           = \frac{Total insuratio for 92 days}{Period}

               Where, Total insurance for 92 days = $ 5,980

                                                               Period = 92 days

               From the values, equation becomes,

                                                                            =\frac{5980}{92}

                                                                           = $ 65 per day

Step:2

              Insurance per day after the 92 days,

                                                                           = $ 97

               Amount Pay for that day than it paid per day during the first period of time,

                                                                            =(97-65)

                                                                           = $32

Result:

             The triangle pay $32 more for that day than it paid per day during the first period of time, if  the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the  insurance beyond the 92 days costs $97 per day.

                                                                         

8 0
3 years ago
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d
kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0
3 years ago
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