All categories

3 years ago

What time is 7 1/2 hours before 2:12 am

Mathematics

1 answer:

Advocard [28]3 years ago

5 0

It's 7:18... Because you have to because 7 subtract 2:12 is 7, and half is 30 min...

You might be interested in

One half of the birds at the pet store are yellow. Tara buys one of the yellow birds. Then one third of the birds at the store a

Viktor [21]

Well, y=ny
2(y-1)=ny
(where ny is not-yellow)
You get y=2y-2 or y=2. You had two yellow birds and two other types.

3 0

3 years ago

Read 2 more answers

The Height of a ramp is 11 inches and the length of its slanted side it 61 inches. What is the length of the base of the ramp?

o-na [289]

Triangle:

39 degrees, 33 degrees, 108 degrees

Side opposite the 108 degrees is 360 feet.

length asked for is d

Hope this helped you! Brainliest? :)

5 0

3 years ago

Can anyone help don’t understand

makvit [3.9K]

Answer:

Twenty decreased by a number. The question says that "a number" =X.

twenty = 20

decreased = minus

by a number = X

Put this all in a line and you get...

an answer of:

20 - X.

3 0

2 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

If f(x) = 3x + 10 and g(x) = 2x - 4, find (f - g)(x).

torisob [31]

<h3>Answer: Choice A) x+14</h3>

=======================================

Work Shown:

(f-g)(x) = f(x) - g(x)

(f-g)(x) = (f(x)) - (g(x))

(f-g)(x) = (3x+10) - (2x-4)

(f-g)(x) = 3x+10 - 2x+4

(f-g)(x) = (3x-2x) + (10+4)

(f-g)(x) = x+14

4 0

3 years ago