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3 years ago

11

One employee pours 6 ounces of coffee in the large frappuccino.

1 answer:

Reil [10]3 years ago

8 0

Answer:

The employee's action <u>is not following the instructions</u>.

Step-by-step explanation:

The drinks table has some recommendations to make some drinks exclusive to the establishment such as the Large Frapuccino or the Small Chai Tea, which in its first line corresponding to the Large Frapuccino specifies that at least 8 ounces of coffee should be used, which it wants to say is the <u>minimum amount of coffee that can be added to it is 8 ounces</u>, and the value could be higher than that, but never lower, which is why by adding only 6 ounces to the Frapuccino you are totally ignoring the instructions.

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Prove:

Using mathemetical induction:

P(n) = $n^{3}+2n+3n^{2}$

for n=1

P(n) = $1^{3}+2(1)+3(1)^{2}$ = 6

It is divisible by 2 and 3

Now, for n=k, $n > 0$

P(k) = $k^{3}+2k+3k^{2}$

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = $(k+1)^{3}+2(k+1)+3(k+1)^{2}$

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Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

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ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

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$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

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$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

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