Pretty simple just place them least to greatest
Answer:
t to the 2 power
Step-by-step explanation:
Keith's bank account starts with $250 and he adds $150 to it every month. If <em>m</em> is the number of months that have passed, then the amount of money (in dollars) in his account is given by
250 + 150<em>m</em>
<em />
Victoria's account starts with $2000 and she removes half of it each month. So after <em>m</em> months, her account has a value of
2000/2^<em>m</em>
<em />
If you were to plot these amounts, then
(a) Keith's account's value is indeed linear - TRUE
(b) Keith is constantly adding money to his account, so its value is increasing - FALSE
(c) Victoria's account's value involves an exponential expression - TRUE
(d) Victoria is removing money, so the value is decreasing - TRUE
Your answers are correct except for (c).
<span>The charity needs at least 1001 entries to raise more than $25000.
Let n be the number of race entries, i be the income of the race, and c the cost of the race.
The money that the 5K brings in is given by
i = 25 * n + 5000
The cost is given by
c = n * 5
Now if the charity needs to raise more than 25000 then the income minus the cost must be greater than 25000.
25000 < i - c
subsituting for i and c
25000 < i - c = (25 * n + 5000 ) - (5 * n)
simplifying results in
25000 < 25*n - 5*n + 5000
25000 < 20*n + 5000
20000 < 20*n
1000 < n
The number of entries must be greater than 1000. Since entries must be an integer the charity needs at least 1001 entries.</span>
Ok so
t=number of text messsages
p=number of picture messages
total number is 33
t+p=33
if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830
we now have 2 equations
t+p=33
18t+45p=830
multiply first equation by -18 and add to second equation
18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236
27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
