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NISA [10]
3 years ago
6

How do I solve this?

Mathematics
1 answer:
Sav [38]3 years ago
8 0
It has no solution. The statement is false for any value x and y therefore the system of equations has no solution.
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The graph of y=x^2 was transformed to Y= -(x+3)^2 +5. Describe all transformations applied to the original function and determin
mina [271]

Hey there!

1. The graph was flipped vertically and now opens downward.

We know this because there is a negative sign in front of the equation:

y= \boxed- (x+3)^2+5

2. The graph was moved 3 units to the left.

We know this because there is 3 added to x inside of the parenthesis. Remember, inside (parenthesis) is opposite and acts on x, outside (parenthesis) is same and acts on y.

y=-(x\boxed{+3})^2+5

3. The graph was moved 5 units up.

We know this because there is 5 added at the end of the equation. It acts on y because it is outside of the parenthesis.

y=-(x+3)^2\boxed{+5}

Hope this helps!

3 0
3 years ago
HELLLPPPP!!!!!!!!!!!!!! I WILL MAKE YOU BRAINLIEST!!!!!!!!!! PLEASE HELP ME!!!
Nimfa-mama [501]

Answer:

  • A. 12x; 5x + 14

Step-by-step explanation:

<u>Perimeter is:</u>

  • P = a + b + c
  • P = 4x - 3 + x + 9 + 8 = 5x + 14

<u>Area is:</u>

  • A = 1/2bh
  • A = 1/2*8*3x = 12x

Correct choice is A

4 0
2 years ago
Read 2 more answers
Use the function y=3/2x+3 to complete the table of values
anastassius [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

Putting all the values of y=9, 6, 0, and -3 to complete the table

FOR y=9

putting y=9

switch sides

subtract 3 from both sides

Hence,

when y=9, x=4

FOR y=6

putting y=6

switch sides

subtract 3 from both sides

Hence,

when y=6, x=2

FOR y=0

putting y=0

switch sides

subtract 3 from both sides

Hence,

when y=0, x=-2

FOR y=-3

putting y=-3

switch sides

subtract 3 from both sides

Hence,

when y=-3, x=-4

Hence, the table becomes:

x                     y

9                    4

6                    2

0                    -2

-3                   -4

8 0
3 years ago
What is the slope of <br><br> 12y=(-24)x
White raven [17]

Answer:

-2

Step-by-step explanation:

First, solve so that y is alone on its side of the equation by dividing both sides of the equation by 12.

12y=(-24)x

y=(-2)x

Therefore, the slope must be -2.

4 0
3 years ago
Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5
ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

-3y=-4x+5 and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

y=\frac{4}{3}x-\frac{5}{3} So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

y-5=-\frac{3}{4}(x-3)* and

y-5=-\frac{3}{4}x+\frac{9}{4} and

y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4} so

y=-\frac{3}{4}x+\frac{29}{4}** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

3 0
3 years ago
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