When i shift the graph of y=2x+5

a school principal orders 75 boxes of chalk. Each box has 12 stick of chalk. The school has 23 teachers. Does the principal have

Darina [25.2K]

So there is 75 boxes of 12 right? You would figure out how much sticks you have by multiplying then you have to give them to 23 teachers. You take the total of sticks and divide among each teacher

I hope this helps :)

3 0

3 years ago

Which ordered pair is a solution for 3x + 4y < 12?

Andre45 [30]

Answer:

D, (1,2)

Step-by-step explanation:

It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).

1. Plug in your x value (1 in this circumstance) and solve:

3(1) + 4y < 12

3 + 4y < 12

2. Plug in your y value (2 in this circumstance) and solve:

3 + 4(2) < 12

3 + 8 < 12

3. Solve

3 + 8 = 11

11 < 12

5 0

2 years ago

Find the area of a rectangle that is 16 3/5in. by 8 9/10

Alenkinab [10]

<h2>Greetings!</h2>

Answer:

Area is 147.74

Step-by-step explanation:

You need to recall that the equation for the area of a rectangle is:

Length * Width = area

So 16 3/5 * 8 9/10 = area

Rearrange so the whole numbers are being multiplied and the fractions are too:

We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:

3/5 * 2 = 6/10

Now the two numbers can be written as 16.6 and 8.9.

Multiply both numbers by 10:

166 * 89 = 14774

Then divide this by 100 (two lots of division by 10)

14774 ÷ 1000 = 147.74

So the area of the rectangle is 147.74!

<h2>Hope this helps!</h2>

8 0

3 years ago

Which three lengths could be the lengths

Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

$4+8=12$

$4+8$

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

$13+11=24$

$13+11>23$

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

$5+12=17$

$5+12$

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

$8+16=24$

$8+16$

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0

3 years ago

A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people

blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

7 0

3 years ago