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BigorU [14]
4 years ago
7

Help me solve this please. thank you!​

Mathematics
1 answer:
alexira [117]4 years ago
6 0

Answer:

In the picture.

Step-by-step explanation:

I don't know about if there are numbers or not.

but you can substitute each one to find the result.

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Factorise the following :​
Ivahew [28]

Answer:

p²q-pr²-pq+r²

p²q-pq-pr²+r²

taking common from two term

pq(p-1)-r²(p-1)

again taking common

(p-1)(pq-r²)

is your answer

3 0
3 years ago
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Find the amount of time.<br><br>I=$450,P=$2400,r=7.5%<br>please help it is due today
SVETLANKA909090 [29]

Answer:

Time=I×100/P×T

=450×100/2400×7.5

=4years

Step-by-step explanation:

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3 years ago
What solution is 33x-33=33x+25?
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3 years ago
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A population of endangered salmon, S(t), starts out with 40 fish and decreases proportionally at a rate of 0.01 fish per year. L
I am Lyosha [343]

The particular solution to the differential equation which describes the number of fish over time will be y = 40(0.99)^t.

<h3>What is an exponent?</h3>

Consider the function:

y = a (1 ± r) ˣ

Where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is a plus sign, then there is exponential growth happening by r fraction or 100r %

If there is a minus sign, then there is exponential decay happening by r fraction or 100r %

A population of endangered salmon, S(t), starts out with 40 fish and decreases proportionally at a rate of 0.01 fish per year. Let t be measured in years.

Let y be the number of fish over time (t).

Then we have

\rm y = 40(1 - 0.01)^t\\\\y = 40(0.99)^t

Then the particular solution to the differential equation which describes the number of fish over time will be y = 40(0.99)^t.

More about the exponent link is given below.

brainly.com/question/5497425

#SPH1

6 0
2 years ago
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