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Art [367]
3 years ago
12

PLEASE HELP! 20 POINTS FOR THIS !! !!!!

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0
Please help and I will help u

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Two sides of a triangle measure 10 centimeters and 15 centimeters what is the measure of the third side
Lady_Fox [76]
Between Greater Than 5 And less than 25

Rule says the sum of two sides must be greater than the third
You get e extremes by subtracting the numbers and the other by adding them
8 0
3 years ago
A rectangular box is 32 cm wide and 36 cm high. If the surface area of the box is 4344 square​ centimeters, find the length of t
AnnZ [28]

To find the surface area, multiply length x width x height.

let "length" = l

l x 32 x 36 = 4344

Simplify

l x (32 x 36) = 4344

l x 1152 = 4344

Isolate the length. Divide 1152 from both sides

(l x 1152)/1152 = (4344)/1152

l = 4344/1152

l = 3.77 (rounded)

3.77 cm is your length.

hope this helps

8 0
3 years ago
Rob measures his go-cart’s speed to be 250 inches per second. What is the go-cart’s speed in miles per hour (to the nearest tent
adoni [48]

Answer:

b.14.2 mph

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
How are observations different from inferences? (choose)
sergejj [24]

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b

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4 0
3 years ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
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