Answer:
X-int: (1/2 , 0) . Y-int: (0 , 4)
Step-by-step explanation:
FOR X
To find the x-intercept, substitute in 0 for Y and solve for X.
0 = -8x + 4
1. Move 4 to the left side so it's -4 = -8x
2. Divide by -8 to isolate X so it's -4/-8 = x
3. The negatives cancel out and become positive
4. Answer: X = 1/2
FOR Y
To find the y-intercept, substitute in 0 for X and solve for Y.
Y = -8(0) + 4
1. Since anything multipled by 0 is 0, it simply becomes Y = 4.
Answer: Y = 4
Answer:
Face, beacuse it's pointing at the flat surface
Given f(x) = x^2 + 1 and g(x) = x-2
a. Find (f-g)(-2)
[f-g](x) = f(x) - g(x) = x^2-x+3
[f-g](-2) = (-2)^2-(-2)+3 = 9
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b. Find f[g(5)]
f[g(5)] = f[5-2] = f[3] = 9+1 = 10
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problem a.
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(f-g)(x) = f(x) - g(x)
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(f-g)(-2) = f(-2) - g(-2)
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f(x) = x^2 + 1
f(-2) = (-2)^2 + 1
f(-2) = 4+1
f(-2) = 5
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g(x) = x-2
g(-2) = -2-2
g(-2) = -4
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f-g(-2) = f(-2) - g(-2) = 5 - (-4) = 5 + 4 = 9
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answer for a is:
f-g(-2) = 9
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problem b.
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g(x) = x-2
g(5) = 5-2
g(5) = 3
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f(x) = x^2 + 1
f(g(5)) = (g(5))^2 + 1
since g(5) = 3, equation becomes:
f(g(5)) = 3^2 + 1
f(g(5)) = 9 + 1 = 10
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answer for b is:
f(g(5)) = 10
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in general, you substitute whatever value is replacing x in the equation to get your answers.
looking at problem b in this way, we would get a general solution as follows:
f(x) = x^2 + 1
g(x) = x-2
substitute g(x) for x:
f(g(x)) = (g(x))^2 + 1
substitute the equation for g(x) on the right hand side.
f(g(x)) = (x-2)^2 + 1
remove parentheses:
f(g(x)) = x^2 - 4*x + 4 + 1
simplify:
f(g(x)) = x^2 - 4*x + 5
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substituting 5 for x:
f(g(5)) = (5^2 - 4*5 + 5
simplifying:
f(g(5)) = 25 - 20 + 5
f(g(5)) = 10
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answer is the same as above where we first solved for g(5) which became 3, and then substituted that value in f(g(x)) which made it f(3)).
Hope this helps!
Area around
we see that all side are 4 legnth
therfor we have a cube
cube has 6 sides tha are sqyares
area of squaer=side^2
side=4
so
SA=6s^2
SA=6(4)^2
SA=6(16)
SA=96 cm^2
what you did is you found the volume
